(y-3)^2+(y-6)(y+5)=9

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Solution for (y-3)^2+(y-6)(y+5)=9 equation: 



(y-3)^2+(y-6)(y+5)=9

We move all terms to the left:

(y-3)^2+(y-6)(y+5)-(9)=0

We multiply parentheses ..

(+y^2+5y-6y-30)+(y-3)^2-9=0

We get rid of parentheses

y^2+5y-6y+(y-3)^2-30-9=0

We add all the numbers together, and all the variables

y^2-1y+(y-3)^2-39=0

We move all terms containing y to the left, all other terms to the right

y^2-1y+(y-3)^2=39

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